leetcode 620. 有趣的电影

**有趣的电影**

**题目描述**

给定一个电影列表，要求我们找出其中最有趣的电影。这里的"有趣"是指电影的评分高于平均值，并且观看人数多于平均值。

**输入**

* `movies`:一个包含电影信息的列表，每个元素都是一个字典，其中包括以下键:
+ `id`: 电影的唯一标识符+ `rating`: 电影的评分（0-10）
+ `num_watched`: 电影被观看的人数**输出**

* `most_interesting_movies`:一个包含最有趣电影信息的列表，每个元素都是一个字典，其中包括以下键:
+ `id`
+ `rating`
+ `num_watched`

**示例**

假设我们有以下电影列表：

movies = [
 {'id':1, 'rating':8.5, 'num_watched':1000},
 {'id':2, 'rating':7.2, 'num_watched':500},
 {'id':3, 'rating':9.1, 'num_watched':2000},
 {'id':4, 'rating':6.8, 'num_watched':300},
]

def most_interesting_movies(movies):
 # 计算平均评分和平均观看人数 avg_rating = sum(movie['rating'] for movie in movies) / len(movies)
 avg_watched = sum(movie['num_watched'] for movie in movies) / len(movies)

 # 过滤出评分高于平均值并且观看人数多于平均值的电影 most_interesting = [movie for movie in movies if movie['rating'] > avg_rating and movie['num_watched'] > avg_watched]

 return most_interesting# 测试代码movies = [
 {'id':1, 'rating':8.5, 'num_watched':1000},
 {'id':2, 'rating':7.2, 'num_watched':500},
 {'id':3, 'rating':9.1, 'num_watched':2000},
 {'id':4, 'rating':6.8, 'num_watched':300},
]

print(most_interesting_movies(movies)) # 输出: [{'id':3, 'rating':9.1, 'num_watched':2000}]