AcWing4118. 狗和猫

**狗和猫**

**题目描述**

在一个小镇上，住着很多只狗和猫。每只动物都有自己的名字、年龄和性别。现在，我们需要根据这些信息来计算出镇上的狗和猫的总数，以及各个年龄段的狗和猫的数量。

**输入格式**

第一行：两个整数n,m（表示小镇上有n只狗，m只猫）。

接下来n+m行，每行代表一个动物，包含三个整数：id（从1到n+m）、age（年龄）和sex（0表示是狗，1表示是猫）。

**输出格式**

第一行：两个整数，分别表示小镇上有多少只狗和猫。

接下来每个年龄段的狗和猫数量，按照年龄从小到大排序，每行一个数字。

**代码实现**

import sys#读取输入数据n, m = map(int, input().split())
data = []
for _ in range(n + m):
 id, age, sex = map(int, input().split())
 data.append((id, age, sex))

# 将狗和猫分开存储dogs = [(id, age) for id, age, sex in data if sex ==0]
cats = [(id, age) for id, age, sex in data if sex ==1]

# 计算各个年龄段的狗和猫数量dog_counts = {}
cat_counts = {}
for id, age in dogs:
 dog_counts[age] = dog_counts.get(age,0) +1for id, age in cats:
 cat_counts[age] = cat_counts.get(age,0) +1# 输出结果print(len(dogs), len(cats))
for i in range(100):
 print(dog_counts.get(i,0), end=' ')
sys.stdout.write('
')
for i in range(100):
 print(cat_counts.get(i,0), end=' ')

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