LeetCode 75 第一题(1768)交替合并字符串

**LeetCode75 第一题: 交替合并字符串**

### 题目描述给定两个以空格为分隔的字符串 `s1` 和 `s2`,返回一个新字符串,其中交替取 `s1` 和 `s2` 中的字符。

### 示例* 输入:`s1 = "hello", s2 = "world"`
输出: `"hweolrllod"`
* 输入:`s1 = "abc", s2 = "pqr"`
输出: `"apbqcr"`

### 解决方案#### 方法1: 使用 Python 的列表推导式

def mergeAlternately(s1, s2):
 """
 交替合并两个字符串 Args:
 s1 (str): 第一个字符串 s2 (str): 第二个字符串 Returns:
 str: 合并后的新字符串 """
 # 确保输入的都是字符串类型 assert isinstance(s1, str) and isinstance(s2, str), "输入必须是字符串"
 # 确保两个字符串长度相等 assert len(s1) == len(s2), "两个字符串长度不一致"
 # 使用列表推导式交替取 s1 和 s2 中的字符 merged = [char1 + char2 for char1, char2 in zip(s1, s2)]
 # 将列表转换为字符串并返回 return ''.join(merged)

# 测试用例s1 = "hello"
s2 = "world"
print(mergeAlternately(s1, s2)) # 输出: "hweolrllod"

s1 = "abc"
s2 = "pqr"
print(mergeAlternately(s1, s2)) # 输出: "apbqcr"

def mergeAlternately(s1, s2):
 """
 交替合并两个字符串 Args:
 s1 (str): 第一个字符串 s2 (str): 第二个字符串 Returns:
 str: 合并后的新字符串 """
 # 确保输入的都是字符串类型 assert isinstance(s1, str) and isinstance(s2, str), "输入必须是字符串"
 # 确保两个字符串长度相等 assert len(s1) == len(s2), "两个字符串长度不一致"
 # 使用 zip 函数交替取 s1 和 s2 中的字符 merged = ''.join(a + b for a, b in zip(s1, s2))
 return merged# 测试用例s1 = "hello"
s2 = "world"
print(mergeAlternately(s1, s2)) # 输出: "hweolrllod"

s1 = "abc"
s2 = "pqr"
print(mergeAlternately(s1, s2)) # 输出: "apbqcr"

import itertoolsdef mergeAlternately(s1, s2):
 """
 交替合并两个字符串 Args:
 s1 (str): 第一个字符串 s2 (str): 第二个字符串 Returns:
 str: 合并后的新字符串 """
 # 确保输入的都是字符串类型 assert isinstance(s1, str) and isinstance(s2, str), "输入必须是字符串"
 # 确保两个字符串长度相等 assert len(s1) == len(s2), "两个字符串长度不一致"
 # 使用 zip_longest 函数交替取 s1 和 s2 中的字符 merged = ''.join(a + b for a, b in itertools.zip_longest(s1, s2))
 return merged# 测试用例s1 = "hello"
s2 = "world"
print(mergeAlternately(s1, s2)) # 输出: "hweolrllod"

s1 = "abc"
s2 = "pqr"
print(mergeAlternately(s1, s2)) # 输出: "apbqcr"